A copper rod of 50mm diameter is subjected to tensile load of 5000 newtons. Calculate the stress.
a) 22x25/28 sq. cm
b) 254.45 N/cm2
c)22x25 sq. cm
d) None of these
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Answer:
22*25sq unit
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Step-by-step explanation:
Area if cross section = 50mm = 50 / 1000= .050m
Force = 5000 N
Stress = ?
Stress = Force applied / Area of cross section
Stress = 5000 / .050
Stress = 100000
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