A copper rod of diameter 1 cm and length 8 cm is drawn into a wire of length 18 m of uniform thickness.
Find the thickness of wire.
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Answer:
The volume of the rod = π×(
2
1
)
2
×8=2π cm
3
The length of the new wire of the same volume = 18 m = 1800 cm
If r is the radius ( in cm ) of cross-section of the wire, its voume = π×r
2
×1800 cm
3
Therefore,
π×r
2
×1800=2π
r
2
=
900
1
r=
30
1
So, the diameter of the cross section, i.e., the thickness of the wire is
15
1
cm, i.e., 0.67 mm (approx.)
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