a copper sphere of 100 g mass is heated to raise its temperature to 100c and is released in water of mass 195 g and temperature 20c in a copper calorimeter. if the mass of the calorimeter is 50 g, what will be the maximum temperature of water? (specific heat of copper =0.1 cal/gc,)
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Answered by
1
Answer:
Heat given = Heat taken
(100) (0.1)(T-75) = (100)(0.1)(45) + (170)(1)(45) 10(T-75)=450 + 7650 = 8100
T-75-810
T = 885 °C
Heat given = Heat taken
(100) (0.1)(T-75)= (100) (0.1) (45) + (170)(1)(45) 10(T-75) = 450+ 7650 = 8100
T-75=810
T = 885°C
Answered by
0
Answer:
Heat given = Heat taken
(100) (0.1)(T-75) = (100)(0.1)(45) + (170)(1)(45) 10(T-75)=450 + 7650 = 8100
T-75-810
T = 885 °C
Heat given = Heat taken
(100) (0.1)(T-75)= (100) (0.1) (45) + (170)(1)(45) 10(T-75) = 450+ 7650 = 8100
T-75=810
T = 885°C
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