Question

A copper sphere of mass 2g contains nearly 2 x 10^22 atoms. The charge on the nucleus of each atom is 29e-. What fraction of the electrons must be removed from the sphere to give it a charge of +2 microcolulombs?

Answer 1

Answer:

Explanation:

Nucleus. The nucleus of an atom is comprised of protons and neutrons; it is therefore positively charged. The number of protons within the nucleus of a given atom is equal to the atomic number of the corresponding element, which can be found on the pNucleus. The nucleus of an atom is comprised of protons and neutrons; it is therefore pNucleus. The nucleus of an atom is comprised of protons and neutrons; it is therefore positively charged. The number of protons within the nucleus of a given atom is equal to the atomic number of the corresponding element, which can be found on the periodic table.ositively charged. The number of protons within the nucleus of a given atom is equal to the atomic number of the corresponding element, which can be found on the periodic table.eriodic table.

Answer 2

$\huge\boxed{\blue{Answer:-}}$

$Total \: no. \: of \: electrons =29 \times 2 \times {10}^{22} \\ Electrons \: removed = \frac{2 \times {10}^{ - 6} }{1.6 \times {10}^{ - 19} } = 1.25 \times {10}^{13} \\ Ratio \: is \: 2.16 \times {10}^{ - 11}$