a copper sphere of radius 3m is melted and recasted into circular cone of radius 3cm .find the radius of the base and slant height of the cone.
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volume of sphere=volume of cone.
4/3 πr3 =1/3πr2h
4/3×3×3×3=1/3 ×9×h
36=3h
h=12
slant height = √r2 +h2
=√3square +12square
=√9+144
=√153
4/3 πr3 =1/3πr2h
4/3×3×3×3=1/3 ×9×h
36=3h
h=12
slant height = √r2 +h2
=√3square +12square
=√9+144
=√153
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hope I will help you
OM NAMAH SHIVAAY
OM NAMAH SHIVAAY
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