A copper vessel of mass 1.35 kg contains 6.75 kg of water at a temperature of 25 deg. C. Find the heat required to warm the vessel and water to 90 deg. C. Take specific heat of copper = 0.406 kJ/kg K and specific heat of water = 4.187 kJ/kg K.
ANS=1872.673 kJ
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Answer:
The heat required is 1872.67275 KJ.
Explanation:
The given data :-
Mass of copper vessel ( m₁ ) = 1.35 kg.
Mass of water ( m₂ ) = 6.75 kg.
Initial temperature ( T₁ ) = 25° C = 273 + 25 = 298 K
Final temperature ( T₂ ) = 90° C = 273 + 90 = 363 K
Specific heat of copper (c₁ ) = 0.406 KJ /kgK
Specific heat of water ( c₂ ) = 4.187 KJ/kgK
So the net heat required ( Q ),
Q = m₁*c₁* ( T₂ - T₁ ) + m₂*c₂ *( T₂ - T₁ )
Q = 1.35 * 0.406*( 363 - 298 ) + 6.75 * 4.187 * ( 363 - 298 )
Q = 35.6265 + 1837.04625 = 1872.67275 KJ.
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