A copper wire 1 mm in diameter carries a current of 12 A. Find the potential difference between two points in the wire that are 100 m apart. Resistivity constant of the copper wire is 1.72 x 10-8 ohm-meter
Answers
Given : A copper wire 1 mm in diameter carries a current of 12 A.
Resistivity constant of the copper wire is 1.72 x 10-8 ohm-meter
To Find : the potential difference between two points in the wire that are 100 m apart
Solution :
R = ρ L/A
ρ = 1.72 x 10⁻⁸ ohm-meter
L = 100 m
A = πr²
r = diameter /2 = 1/2 = 0.5 mm = 5 * 10⁻⁴ m
π = 3.14
A = 3.14 * (5 * 10⁻⁴ )² = 78.5 * 10⁻⁸ m²
R = 1.72 x 10⁻⁸ * 100 / 78.5 * 10⁻⁸
=> R = 2.191 Ω
V = IR
I = 12 A
R = 2.191 Ω
=> V = 12 * 2.191
=> V = 26.292 V
potential difference between two points in the wire that are 100 m apart. = 26.292 V
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