Question

A copper wire has a Cross section area of 7.85 x 10^-7 m².
The no density of Copper is 8.5 x 10^28 m-3. calculate the
drift velocity of electrons through the wire when the
Current is 1.4 ampere.​

Answer 1

Answer:

$\large\mathcal{\red{Answer :-}}$

10-³m/s

Answer 2

Given :

The cross-section area of 7.85 x 10^-7 m²

The no density of Copper is 8.5 x 10^28 m-3

The Current is 1.4 A.

To Find:

Drift velocity of electrons through the wire

Solution:

The drift velocity is given by the formula = I / n e A

where,

vd = drift velocity

I = current flow

n = free electron density

e = charge of an electron

A = cross sectional area

Therefore Vd= 1.4 / 8.5 x 10^28 x  7.85 x 10^-7 x 1.6 x 10^-19

Vd= 1.4 / 106.76 x 10^2

= 0.013 x 10^-2 m/s

The drift velocity is 0.013 x 10^-2 m/s.