A copper wire has a diameter 0.5 mm and of 1.6 ×10^-8 ohm m.whatwill be the length of this wire to make its resistance 10 ohm ? How much does ots resistance change if the diameter is doubled ?
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R = pl/A
so, l = R*A/p
= 10* pi* (0.25 *10^-3)^2 / (1.6* 10^-8)
so, l = R*A/p
= 10* pi* (0.25 *10^-3)^2 / (1.6* 10^-8)
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