A copper wire has a diameter 0.5 mm and resistivity 1.6 into 10 ki power minus 8 ohm metre what will be the the length of this wire to make the resistance of 12 Ohm how much will be the resistance of another copper wires of same length but half the diameter
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Explanation:
Given,
diameter of copper wire = 0.5mm = 5 × 10-⁴ m
resistivity = 1.6 × 10^-8 ohm.m
resistance = 10 ohm
Length = ?
we know,
R = dL/A
where R , d , L and A are resistance , resistivity , length and cross section area.
10 = 1.6 × 10^-8 × L/(πr²)
L = 10 × 3.14 × (2.5 × 10^-4)² × 10^8/1.6
L = 10× 3.14 × 6.25/1.6
L = 122.656 m
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