A copper wire has a diameter 0.5mm and resitivity 1.6 *10^-8ohm m. How much will be the resistance of another copper wire of same length but half the diameter.
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Answer:
Area of cross-section of the wire, A =π (d/2) 2
Diameter= 0.5 mm = 0.0005 m
Resistance, R = 10 Ω
We know that
1st image
∴ length of the wire = 122.72m
If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m
Let new resistance be Rʹ
2nd image
∴ the new resistance is 2.5 Ω
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