Question

A copper wire has a diameter of 0.5 mm and resistivity of 1.6 x 10–8 ohm m. What will

be the length of this wire to make its resistance 10ohm? How much does the

resistance change if the diameter is doubled?

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Answer 1

Answer:

Area of cross-section of the wire, A =π (d/2) 2

Diameter= 0.5 mm = 0.0005 m

Resistance, R = 10 Ω

We know that

∴ length of the wire = 122.72m

If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m

Let new resistance be Rʹ

Explanation:

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Answer 2

Answer:

New length of wire is 122.6 m

new resistance is 2.5 Ω

Resistance change is 10 - 2.5 = 7.5 Ω

Hope it helps you