A copper wire has a diameter of 2cm & resistivity of 10to the power 7 ohm meter . What will be the length of this wire to make it’s resistance 50 ohm ? How much does the resistance change if the diameter is doubled
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Answer:
1.57×10⁻⁵ m
Explanation:
d = 2cm
=> r = 1cm
ρ = 10⁷ Ωm
R = 50Ω
R = ρl/A = ρl/(πr²)
=> 50 = 10⁷×l/(3.14×1²)
=> l = 50×3.14×1/(10⁷) m
=> l = 157/10⁷ m = 1.57×10⁻⁵ m
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