a copper wire has a resistanc R is cut into 20 equal parts and two pieces are connected in series and then 20 such combination are joined in parallel . the new combination will have resistance.
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Answer:
Correct option is
D
25
R
Resistance of metallic wireR
When cut into 10 equal parts, each part will have resistance =
10
R
When two pieces are joined in series, then R
′
=
10
R
+
10
R
=
10
2R
=
5
R
Now each such combinations are joined in parallel then
R
′′
1
=
5
R
1
+
5
R
1
+
5
R
1
+
5
R
1
+
5
R
1
=
5
R
5
=
R
25
⇒R
′′
=
25
R
Ω
Explanation:
hope this helps you
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