Question

A copper wire has a resistance of 0.6ohm. Another copper wire of the same mass as the first one is double in length of the first. Find the resistance of the second wire

Answer 1

Answer:

R^ = 2R = 2 (0.6) =1.2 bbbb

Answer 2

Electricity

We know that

R = p.1/A [A= area of the bisected conductor, P = is the resistivity of the conductor ] … (1)

Given,R = 0.6 ohm

Let L be the length of the conductor and M be the mass of the conductor

So M = L.A …(2)

Again Given the length of the second conductor = 2L, let the area of the bisected conductor be B

Therefore,

M = 2L.B

=> B = M/2L … (3)

So the resistance of the second conductor will be

= p.1/B

= p{1/(M/2L)}

= p(2L/M)

= p(2/A) … [from no 2]

= 2.p/A

= 2R … [from no 1]

= 1.2 ohm

That’s it

Hope it helped

(0_o)