A copper wire has a resistance of 10 ohm. It is streched by one-tenth of its original lenght. Then its resotance will be
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hii mate
we know that length,if increased current flowing decrease that is resistance increase.
x=10 ohm
1/10x=y
y=10*1/10
y=1 ohm
hence 1 ohm of resistance increased in 10
hence answer is 11 ohm
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