A copper wire has diameter 0.5 mm and resistivity of 1.6 ×10^-8 ohm metre what will be length of this wire to make the resistance of 10 ohm
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Answer:
Given, diameter, d=0.5 mm
resistivity, ρ=1.6×10
−8
Ωm
Resistance, R=10 Ω
Let the length of wire be l.
A=πd
2
/4
R=ρl/A
=
πd
2
/4
pl
⟹l=
4ρ
Rπd
2
l=
4×1.6×10
−8
10×3.14×(0.5×10
−3
)
2
l=122 m
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