a copper wire has diameter 0.5 mm and resistivity of 1.6 into 10 power minus 8 m what will be the length of the wire of neck its resistance 10 how much does the resistance change its the diameter is doubled
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cross-section of the wire, A =? (d/2) 2
Diameter= 0.5 mm = 0.0005 m
Resistance, R = 10 ?
We know that
in image
? length of the wire = 122.72m
If the diameter of the wire is doubled, new diameter=2 0.5=1mm=0.001m
Let new resistance be R?
now in 2nd image
hence the new resistance is 2.5
A.F
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