Question

A copper wire has diameter 0.5mm and resistivity of 1.6X10-8Ωm. what be the length of this
wire to make its resistance 10Ω?

Answer 1

Answer:

100

hope it's help you!!!

Answer 2

Answer:

L = 122.7m (approx)

Explanation:

According To The Question:

R = 10Ω
d = 0.5mm
r  = 0.25mm ⇒ $0.25$ × $10^{-3}$
ρ = $1.6$ × $10^{-8}$
A = ?
L = ?

So First, We Find Area.
Area = $\pi r^{2}$
        =  $\pi$ × $r^{2}$

        =  $\pi$ × ( $0.25$ × $10^{-3}$ )²

        = $\pi$ × ( $0.625$ × $10^{-6}$ )

        = $\pi$ × ( $62.5$ × $10^{-8}$ )

So, Area =  $\pi$ × ( $62.5$ × $10^{-8}$ )

Now, We Substitute Area In The Equation Below:

$Equation: L = \frac{RA}{p}$

      $L = \frac{RA}{p}$

      $L = \frac{10* \pi*62.5*10^{-8} }{1.6 * 10^{-8} }$

      $L = \frac{10* \pi*62.5}{1.6 } (Cancel 10^{-8} )$

      $L = \frac{10* 3.14*62.5}{1.6}$

      $L = \frac{31.4*62.5}{1.6}$

      $L = \frac{196.25}{1.6}$

      $L = \frac{196.25}{1.6} * \frac{10}{10}$

      $L = \frac{1962.5}{16}$

      $L = 122.65625m$

      $L = 122.7m$ (approx)

So, The Length Of The Wire is 122.7m.

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