A copper wire has diameter 0.5mmand resistivity of 1.6×10^-8ohmmeter What is the length of tge wire to make a resistance of 10ohm
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Answer:
Area of cross-section of the wire, A =π (d/2) 2
Diameter= 0.5 mm = 0.0005 m
Resistance, R = 10 Ω
We know that
∴ length of the wire = 122.72m
If the diameter of the wire is doubled, new diameter=2×0.5=1mm=0.001m
Let new resistance be Rʹ
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