Question

a copper wire has diameter is 0.5 mm and resistivity is 1.6 into 10 to the power minus 6 ohm centimetre. how much of this wire would be required to make 10 ohm coil? how much does the resistance if the wire is doubled on it​

Answer 1

Explanation:

given:

diameter of copper wire=0.5 mm×5×10^-4m

resistivity=1.6×10^-8ohm.m

resistance=10 ohm

length=?

we know:

R=dL/A

where R,d,L and A are resistance, resistivity , length and area of cross section...

10=1.6×10^-8×L/(πr²)

L=10×3.14×(2.5×10^-4)²×10^8/1.6

L=10×3.4×6.25/1.6

L=122.656 m

hope it will help you NANBA✔❌