Question

A copper wire has diameterb1mm and resistivity 1.6 into 10 to the power 3 ohm what would be the lenth of the wire to make a resistance of 15 ohm
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Answer 1

Answer:

Given, Diameter=0.5mm,resistivity=1.6×10−8Ω−m,resistance=10Ω

we know that R=ρA1⇒1=ρRA

Where A is the area of the cross-section,

=1.6×10−810×3.14×(20.0005)2=122.7m

Thus the length of the wire is 122.7m

Explanation:

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