Question

A copper wire has length L and cross-sectional area A. Its resistance is R. If we halved

the length and halved the diameter of wire, then what will be the resistance of this wire?​

Answer 1

Answer:

the resistance of the wire will also halved R/2

Answer 2

Explanation:

$\huge\mathbf{\boxed{\red{\boxed{\green{Answer }}}}}$

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Given,

Length Of wire = L

Area of cross-section = A

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To find :-

Resitance of wire if it is halved

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New Units :-

Length = L/2

Area = A/2

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$\huge{\fcolorbox {red} {yellow} { R = L/A}}$

$r \: = \frac{l}{2} \times \frac{2}{a} \\ r = \frac{l}{a}$

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