A copper wire has resistant 16 ohm it is melted and drawn into a wire half of its length calculate the resistance of new wire and precentage change in resistance find the change in resistivity also
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Since ii Melted means Volume constant
R = p L/A
V = A×L
R = pL^2/V
R ~ L^2 .
Resistance is 1/4 of Intial resistance
R = 4ohm
Decrease by 75%
Resistivity not change It does not depend on length
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