Question

A copper wire having resistance 10 ohm is
stretched so that its radius decreases
by 3%. What is the resistance of this
wire after stretching.​

Answer 1

Answer:

the residence of a wire can be expressed as R -- pl /A where p is the resistivity of the material l is the length of a wire A is the cross sectional area of the wire since streching of the wire does not change the column of wire

Explanation:

5 - IA constant 1 V/SA when radius is decreased by 0.1 percent the area decreased to 0.999.A. Thus the residence become R P .V / A decided A equals to P V devidd A ... P - V devided 0 .999 thus percentage increase in resistance R-R devide R multiple by 100 percent equals to 0.4 percent .... I hope this will help you thanks