A copper wire is 3mm in diameter is wound about a cylinder whose length is 12 cm and diameter 10cm so as to cover the Csa of ar of cylinder . Find the length and mass of wire
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Hloo dear....!!!!
Radius of wire =0.3
length of cylinder =12 cm
diameter = 10cm
Density is given to be 8.88gmcm³
CSA of cylinder = 2πrh
2 x 22/7 x 5 x 12
120 π cm²
l of wire = area /width
= 120π / 0.3
=1256
volume of wire = πr²h
3.14 x o.15² x 1256
88.7364cm³
mass = density x volume
8.88 x 88.7364
= 788g (approx)
hope it helps
@sonu..
Radius of wire =0.3
length of cylinder =12 cm
diameter = 10cm
Density is given to be 8.88gmcm³
CSA of cylinder = 2πrh
2 x 22/7 x 5 x 12
120 π cm²
l of wire = area /width
= 120π / 0.3
=1256
volume of wire = πr²h
3.14 x o.15² x 1256
88.7364cm³
mass = density x volume
8.88 x 88.7364
= 788g (approx)
hope it helps
@sonu..
johhnyty:
Thanks a lot.. Density was 8.88 I forgot in question... Anyways I reminded u while u were answering.. Thanks a a lot it helped me
Answered by
5
Heya ....
====== Answer =======
Given :
Radius of wire = 0.3
Lenght = 12 cm
Diameter = 10 cm
Density = 8.88 gm cm^3
• CSA of cylinder = 2πrh
= 2*22/7*5*12
= 120 cm ^2
• Hight of wire = area/widht
= 120π/0.3
= 1256 cm
• Volume = πr^2 h
= 3.14*0.15^2*1256
= 88.7364 cm^3
• Mass = density X volume
= 8.88*88.7364
= 788g ( approx )
Thank you
====== Answer =======
Given :
Radius of wire = 0.3
Lenght = 12 cm
Diameter = 10 cm
Density = 8.88 gm cm^3
• CSA of cylinder = 2πrh
= 2*22/7*5*12
= 120 cm ^2
• Hight of wire = area/widht
= 120π/0.3
= 1256 cm
• Volume = πr^2 h
= 3.14*0.15^2*1256
= 88.7364 cm^3
• Mass = density X volume
= 8.88*88.7364
= 788g ( approx )
Thank you
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