A copper wire is bent in the form of a square encloses an area of 121 sqcm.If the same wire is bent into the form of a circle.Find the area of the circle
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The Area of a square is given by Side2; in this case A = 121cm2 = S2
So, S = √121cm2 = 11cm
The perimeter of this square will be 4 x S or 44cm, which will be the circumference of the circle.
We know the circumference of a circle = pi x Diameter, so we can calculate the diameter, which will be 44cm ÷ pi ≅ 14cm
From the diameter, we can figure the radius, which is 1/2 the diameter, or 7cm
Finally, we can figure the Area of the circle by A = pi r2 = 3.1415 x 7cm2 = 154cm2
HOPE IT HELPS
So, S = √121cm2 = 11cm
The perimeter of this square will be 4 x S or 44cm, which will be the circumference of the circle.
We know the circumference of a circle = pi x Diameter, so we can calculate the diameter, which will be 44cm ÷ pi ≅ 14cm
From the diameter, we can figure the radius, which is 1/2 the diameter, or 7cm
Finally, we can figure the Area of the circle by A = pi r2 = 3.1415 x 7cm2 = 154cm2
HOPE IT HELPS
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We know,
Area of a square = side²
∴ Side of the square with area 121 cm² = √121 = 11 cm.
Perimeter of the square = 4 x 11 = 44 cm.
Now, this wire is bent to form a circle.
∴ 2πr = 44 cm.
∴ r = 7cm.
Now, area of circle =πr²
= 22/7 x 7x 7 = 154 cm².
Hope it helped!
NISHTHA.
Area of a square = side²
∴ Side of the square with area 121 cm² = √121 = 11 cm.
Perimeter of the square = 4 x 11 = 44 cm.
Now, this wire is bent to form a circle.
∴ 2πr = 44 cm.
∴ r = 7cm.
Now, area of circle =πr²
= 22/7 x 7x 7 = 154 cm².
Hope it helped!
NISHTHA.
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