a copper wire is stretched to make it 0.2 %longer . what is the percentage change in its resistance
Answers
Answered by
22
ANS : 0.4%
*EXPLANATION*
Whenever a resistance wire is stretched then its volume is unchanged and hence the
resistance equal to (rho × L÷A)
therefore R is equal to (rho × L ÷V ) L
= (rho×L^2 )V
rho and V are constants
and hence the R proportional to square of L
and then (Delta R /R)=( 2 x of delta L÷L) therefore
DOUBLE OF THE change of the percentage of the length of the resistance wire is equal to change of the percentage of the resistance
means the 0.2% change in this question for the length of a substance wire and hence the electrical resistance changed as double of the 0. 2 = 0.4% .
SO ANSWER 0.4%
Answered by
5
Answer:
Ans: 0.4%
Explanation: Hope its clear.
Attachments:
Similar questions