A copper wire is wound on wooden frame whose shape is equitlateral triangle if the linear dimensions of the each side of frame is increased by a factor of 3 keeping number of turns per unit length of coil same then the self inductance of the coil
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According to the problem the wire is wound on wooden frame having shape like equilateral triangle
let the length of each side is a
then the total length,l is 3a
therefore the area, A= √ 3/4 a^2
Let the diameter of the wire is r
Therefore the self inductance= μ0n^2Al=μ0n^2(√ 3/4 a^2)dN where N is the number of turns.
Therefore the self inductance increases 3 times
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