Question

A copper wire of 5 metre at 15 degree celsius is heated to 35 degree celsius. Calculate the increase in length of the wire if coefficient of linear expansion of copper is 1.7x10^-5C -1​

Answer 1

Answer:

The increase in length of the wire is 1.7 × 10⁻³ m

Explanation:

Given :

• A copper wire of 5 m at 15°C is heated to 35°C.

• The coefficient of linear expansion of copper is 1.7×10⁻⁵ C⁻¹

To find :

the increase in length of the wire

Solution :

The change in length due to linear expansion is given by,

$\longrightarrow \tt \Delta L = L \alpha \Delta T$

where

L denotes the initial length

α denotes the coefficient of linear expansion

ΔT denotes the temperature difference

We're given,

L = 5 m

α = 1.7×10⁻⁵ C⁻¹

ΔT = (35°C - 15°C) = 20°C

Substituting the values,

ΔL = 5 × 1.7×10⁻⁵ × 20

ΔL = 1.7 × 10⁻⁵ × 100

ΔL = 1.7 × 10⁻³ m ( = 0.17 cm )

∴ The increase in length of the wire is 1.7 × 10⁻³ m

Answer 2

Answer:

The increase in length of the wire is 1.7 × 10⁻³ m

Explanation:

Given :

A copper wire of 5 m at 15°C is heated to 35°C.

The coefficient of linear expansion of copper is 1.7×10⁻⁵ C⁻¹

To find :

the increase in length of the wire

Solution :

The change in length due to linear expansion is given by,

$\longrightarrow \tt \Delta L = L \alpha \Delta T⟶ΔL=LαΔT$

where

L denotes the initial length

α denotes the coefficient of linear expansion

ΔT denotes the temperature difference

We're given,

L = 5 m

α = 1.7×10⁻⁵ C⁻¹

ΔT = (35°C - 15°C) = 20°C

Substituting the values,

ΔL = 5 × 1.7×10⁻⁵ × 20

ΔL = 1.7 × 10⁻⁵ × 100

ΔL = 1.7 × 10⁻³ m ( = 0.17 cm )

∴ The increase in length of the wire is 1.7 × 10⁻³ m