A copper wire of certain length has a resistance of 10 ohm. What will be its resistance after strectching to double its length
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Answered by
1
Answer:
Resistance will become 4 times .ie.40 ohm
Answered by
1
Answer:
40ohm
R = p L/A
V = A×L
Area = V/L
R = p l^2/V
R ~ L^2
length Doubled
R ~ 4L^2
means 4 times
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