A copper wire of cross-section A is under a tension T. Its
Young's modulus is Y and Poisson's ratio o. The decrease
in cross-section of wire will be
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Answer:
Correct option is
C
AY
2σT
d
Δd
=−σ
l
Δl
=−σ
AY
T
ThusΔd=−σd
AY
T
,henceΔA=Δ(π/4d
2
)=2.π/4.dΔd
HenceΔA=2.π/4.d.d.(
AY
−σT
)=2
Y
−σT
orDecrease=−
A
ΔA
=
AY
2σT
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