A copper wire of diameter 1.02 mm carries
a current of 1.7 amp. Find the drift velocity
(vd) of electrons in the wire.
Given n, number density of electrons in
copper = 8.5 1027 /m3.
(1) 1.75 mm/sec
(2) 1.25 mm/sec
(3) 0.15 mm/sec
(4) 1.5 mm/sec
Answers
Answered by
0
i think option b should be correct.
TwinklePrajapat:
option 4th is correct
how??
oh sorry 4 th is correct
I = 1.7 A
J = current density
= 2 3 2
I 1.7
r (0.51 10 )
= nevd
= 8.5 1027 (1.6 10-19 ) vd
vd = 3 2 27 19
1.7
(0.51 10 ) 8.5 10 1.6 10
= 1.5 10-3 m/sec. = 1.5 mm/sec.
J = current density
= 2 3 2
I 1.7
r (0.51 10 )
= nevd
= 8.5 1027 (1.6 10-19 ) vd
vd = 3 2 27 19
1.7
(0.51 10 ) 8.5 10 1.6 10
= 1.5 10-3 m/sec. = 1.5 mm/sec.
It's ok
thanks for the answer!!!!
your welcome
follow me
no i don't FOLLOW anyone
ok
Similar questions