a copper wire of diameter 1 cm had a resistance of 0.15 ohm. It was drawn under pressure so that its diameter was reduced to 50%. What is new resistance of wire
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ans will be 2.4
volume will be same as wire is stretched so area × length = constant
in this area is decreased 4 times so length will increase 4 times and by applying formula of resistance 4×4×0.15=2.4
volume will be same as wire is stretched so area × length = constant
in this area is decreased 4 times so length will increase 4 times and by applying formula of resistance 4×4×0.15=2.4
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