A copper wire of length 1.0 m and a steel wire of length 0.5 m having equal cross-sectional areas are joined end to end. The composite wire is stretched by a certain load which stretches the copper wire by 1 mm. If the Young’s modulii of copper and steel are respectively 1.0xx10^(11)Nm^(-2)"and"2.0xx10^(11)Nm^(-2), the total extension of the composite wire is:
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1.25 mm
Explanation:
Yc×(ΔLc/Lc)=Ys×(ΔLs/Ls)
⇒1×1011×(1×10−31)=2×1011×(ΔL50.5)
∴ΔLs=0.5×10−32=0.25mm
Therefore, total extension of the composite
wire =ΔLc+ΔLs
=1mm+0.25m=1.25m
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