a copper wire of length 10cm has a diameter of of 1mm find the resistance offered by its resistivity 2×10‐⁷ ohm/m
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Answer:
Given, Diameter=0.5mm,resistivity=1.6×10
−8
Ω−m,resistance=10Ω
we know that R=ρ
A
1
⇒1=
ρ
RA
Where A is the area of the cross-section,
=
1.6×10
−8
10×3.14×(
2
0.0005
)
2
=122.7m
Thus the length of the wire is 122.7m
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