Question

A copper wire of length 2.2
m and a steel wire of length 1.6 m, both of diameter 3.0 mm, are connected end to end.
When stretched by a load, the net elongation is found to be 0.70 mm. Obtain the load applied.
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Answer 1

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Answer 2

Explanation:

Length of the copper wire = 2.2cm

Length of the steel wire 1 = 1.6cm

Elongation in length ∆1 = 0.5.mm

Radius of Cu wire r1 = 1.5 × 10^-3 m

Y1 = 1.1 × 10^11 N/m^2

Y2 = 2.0 × 19^11 N/m^2

Let f be the stretching force in both wires then,

for Cu wire, Y1 = F/π1^2 × 1^1/∆ 1^1

F = Y1 πr1^2 × ∆ 1^1 / 1^1

= 1.1 × 10^-11/ 2.2 × 22/7 × (1.5 × 10^-3) × 0.5 × 10^3

= 1.8 × 10^2 N

So the stretching force in the copper wire be 1.8 × 10^2 N

hope it helps you

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