Question

A copper wire of length 2m and area of cross section 1.7 *10-6m2 has a resistance of 2*10-2 ohms calculate the resistivity of copper

Answer 1

Given values

l = 2 m

A = 1.7 X 10⁻⁶ m²

R = 2 X 10⁻²

R = (ρl)/A

ρ = (RA)/l = (2 X 10⁻² X  1.7 X 10⁻⁶ )/2 =1.7 X 10⁻⁸Ωm

Answer 2

heyya mate!

here is the answer

given:

length:- 2m(l)

Area of cross-section:- 1.7*10^-6(A)

Resistivity of wire:-2*10^-2(R)

we know that ,

R = el/A

2*10^-2 = e*2/1.7*10^-6

e = RA/l

= 2*10^-2 * 1.7*10^-6/2

=1.7*2 *10^-2*10^-6/2

=3.4 * 10^-8/2

which is equal to

1.7*10^-8 ohm m

hope it helps ,

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