CBSE BOARD X, asked by Brainlyshine, 1 year ago

A copper wire of length 2m and area of cross section 1.7x10^-6 has a resistance of 2x 10^-2ohmsv.calculate resistivity of copper

Answers

Answered by Anonymous
3

Answer:

εηηο!

_____________________

Resistivity = R xA /l

putting the values given :-

=>2x 10^-2x1.7x10^-6/2

=>1.7x10^-8Ωm

Mark brainliest hope it helps you

Answered by Anonymous
0

Answer:

The ‘resistivity of copper’ wire is .

Solution:

The resistivity or the specific resistance of a material is the inherent property of each material but it varies depending upon the “length and cross-sectional area” of the material. The resistivity is said to be ‘directly proportional’ to the “cross-section area of the material” and ‘inversely proportional’ to the “length of the material”. The ‘resistance’ of the material acts as the proportionality constant.

Mathematically, the resistivity can be determined using the below equation,

Here, R is the resistance, A is cross-section area and L is the length of the material and ρ is the resistivity.

Thus for the given case, .

So the resistivity is  

Thus the ‘resistivity of copper’ wire is .

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