Question

A copper wire of length 2m and area of cross section is 1.7*10-6m2 has a resistance of 2*10-2ohm.calculate the resisitivity of copper

Answer 1

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Here is Your Answer....!!!
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Actually welcome to the concept of the current electricity .....

So Basiclly we know that ....

R = p × l/A

So as given here .... R = 2 × 10^-2 ohm

l = 2m and A = 1.7 × 10^-6 m^2 ....

So we get that .... p (rho) = R A ÷ l

p = 2 × 10^-2 × 1.7 × 10 ^-6 ÷ 2

p = 1.7 × 10^-8

thus the resistivity is given as 1.7 x 10^-8 .... ohm - metre

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Hope it helps u.....☺

Answer 2

Answer:

Thus, the 'resistivity of copper' write is 1.7x10^-8m

Explanation:

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