A copper wire of length 50 cm and area of cross section 10^6 m^2
carries a current of 0.5 A. If the
resistivity of copper is 1.8 x 10^8 ohm m^2, the electric field across the wire is
Answers
Answered by
2
Answer:
from given data A=2mm
2
ρ=1.7×10
−8
Ωm.
i=1A
V=iR ( from ohms law.)
V=i×
A
ρl
E.l=i×
A
ρl
⇒E=i×
A
ρl
=1A×
2mm
2
1.7×10
−8
Ωm
=8.5×10
−3
m
V
E=8.5×10
−3
m
V
Explanation:
Similar questions