Question

A copper wire of mass 20g carries a current of 6.023A.what fraction of total number of free electrons, present in copper wire flows through
The cross section of copper in 2s.​

Answer 1

Answer:

2*(number of free electrons crossing unit area pf wire per second/number of free electrons in 20g of copper)

Explanation:

We need to find the fraction of total number of free electrons, present in copper wire flows through  the cross section of copper in 2 seconds

• current I = 6.023
• number of free electrons crossing unit area of wire per second =(6.023/1.6 E-19).
• number of free electrons in 20g of copper= N x (20/63.5) where N is the Avogadro number.