A copper wire of resistance 4 ohm is stretched to thrice its original length find the resistance of the stretched wire
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Given:
The resistance of the copper wire R= 4 ohm
The original length l
The stretched length 3l
To find:
The resistance of the original one.
Solution:
The Resistance is directly proportional to the length.
R'=ρl²/V
R=ρ(3l)²/V
Taking the ration of both the terms.
R/R'= 9l²/l²
R=9R'
As the R'=4
Put back in above equation
R=9×4
R=36 ohm
So the resistance of stretched wire is 36 ohm
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