Question

A copper wire of resistance "R" is uniformally stretched till its length is increased to n time the original length. What will be the new resistance?

Answer 1

The resistance of increases as length of the wire increases.

R=rho L/A
New length becomes nL and area decreases by n times
so,
R'=rho nL/A/n
R'=rho n×nL/A
R'=rho n^2L/A
R'=rho L/A(n^2)
R'=n^2R This becomes the new resistance.

Answer 2

Explanation:

rho =l/a

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