Question

A copper wire of resistivity 1.63 x 〖10〗^(-8) Ω-m has cross-section area of 10.3 x 〖10〗^(-4) cm². Calculate length of wire required to make a 20 Ω coil . please follo w me and fast ans​

Answer 1

Answer:

p=1.63×10^-8ohm-m

A=10.3×10^-4cm²

R=20ohm

R=pl/A

l=R×A/p

l=20×10.3×10^-4/1.63×10^-8=126.4m

therefore, length of the wire =126.4m