A copper wire of uniform area of cross-section of 1.54 x 10^-6 m2 carries a current of 3.08 A. The electric field inside the wire, when the resistivity of copper is 1.724 x 10-8 ohm.m, is
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Answer:
from given data A=2mm
2
ρ=1.7×10
−8
Ωm.
i=1A
V=iR ( from ohms law.)
V=i×
A
ρl
E.l=i×
A
ρl
⇒E=i×
A
ρl
=1A×
2mm
2
1.7×10
−8
Ωm
=8.5×10
−3
m
V
E=8.5×10
−3
m
V
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