a copper wire resistance of 30ohm is cut into three equal parts and each part is stretched to twice of its length find the resistance of each part
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Answered by
2
Answer:
HEY
When a resisteor is stretched to double in original length the new resistance becomes four times its original resistance becomes R∝l2
∴ New resistance =4R=4×15=60Ω
Resistance of each part =30Ω
i.e. R1=30ΩandR2=30Ω
When they are conpected in parallel the effective
resistance, RP=
R1R2
R1+R2
=
30×30
30+30
=15Ω
Current, I=
V
RP
=
3
15
=0.2A
Explanation:
pLZ MARK AS BARINLIEST
Answered by
4
Answer:
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