Physics, asked by sanampriya2005, 8 months ago

a copper wire resistance of 30ohm is cut into three equal parts and each part is stretched to twice of its length find the resistance of each part

Answers

Answered by shanya3444455566778
2

Answer:

HEY

When a resisteor is stretched to double in original length the new resistance becomes four times its original resistance becomes R∝l2

∴ New resistance =4R=4×15=60Ω

Resistance of each part =30Ω

i.e. R1=30ΩandR2=30Ω

When they are conpected in parallel the effective

resistance, RP=

R1R2

R1+R2

 

=

30×30

30+30

 

=15Ω

Current, I=

V

RP

 

=

3

15

 

=0.2A

Explanation:

pLZ MARK AS  BARINLIEST

Answered by deepakkchoudhary85
4

Answer:

see the above attachment

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