Question

A copper wire when bent in the form of a circle the area of circle is 121√3 cm square find the circumference enclosed by the wire

Answer 1

C

≈

38.99

hope you got ur answer mark as brinliest if possible

Answer 2

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Area of an equilateral ∆ = √3a²/4
Where a=side
Now, given that -
√3a²/4= 121√3
=>a²=121*4
=> a=11*2= 22
Therefore, length of wire = a+a+a=66
Now, this wire is bent into a circle, so circumference of the circle=2πr=66
=>2*(22/7)r=66
=> r=21/2
Now, area of this circle =πr²
=(22/7)*(21/2)²
=693/2
=346.5cm²