A COPPER WIRE WHEN BENT IN THE FORM OF A SQUARE ENCLOSE AN AREA OF 121 m
If the same WIRE is bent into a circle ,find the area
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a^2 =121
a=11
length of wire =4a =44
2pi r =44
r=7
area = pi r^2
A = 22/7 x(7×7) =154 sqm
a=11
length of wire =4a =44
2pi r =44
r=7
area = pi r^2
A = 22/7 x(7×7) =154 sqm
Rudra18328:
Can explain it how r=7
Please
2 x( 22/7) x r =44
hence (44/7)xr = 44
r =7
O thanks bro
because length of the wire will act as circumference of circle
Ok
welcome
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