Question

A copper wire, when bent in the form of a square, encloses an area of 484 CM². if the same is bent in the form of a circle find the area enclosed by it.(Use π = 22/7)​

Answer 1

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We Have,

Area of the square=484 cm²

$= {(side)}^{2} = {(22)}^{2} {cm }^{2} \\ = side = 22cm$

So, Perimeter Of the square

$=4 (side) = (4 \times 22)cm = 88cm$

Let r be the radius of the circle.Then,

Circumference of the circle=Perimeter of the square

$= 2\pi \: r = 88 \\ = 2 \times \frac{22}{7} \times r = 88 = r = 14cm$

Area of the circle

${\pi \: r}^{2} = \frac{22}{7} \times {(14)}^{2} {cm}^{2} = 616 {cm}^{2}$

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Answer 2

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We Have,

Area of the square=484 cm²

$\begin{gathered}= {(side)}^{2} = {(22)}^{2} {cm }^{2} \\ = side = 22cm \\\end{gathered}$

So, Perimeter Of the square

$=4 (side) = (4 \times 22)cm = 88cm=4(side)=(4×22)cm=88cm$

Let r be the radius of the circle.Then,

Circumference of the circle=Perimeter of the square

$\begin{gathered}= 2\pi \: r = 88 \\ = 2 \times \frac{22}{7} \times r = 88 = r = 14cm\end{gathered}$

Area of the circle

${\pi \: r}^{2} = \frac{22}{7} \times {(14)}^{2} {cm}^{2} = 616 {cm}^{2}$